x^2-2x-320=0

Solution for x^2-2x-320=0 equation:

x^2-2x-320=0

a = 1; b = -2; c = -320;
Δ = b2-4ac
Δ = -22-4·1·(-320)
Δ = 1284
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1284}=\sqrt{4*321}=\sqrt{4}*\sqrt{321}=2\sqrt{321}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{321}}{2*1}=\frac{2-2\sqrt{321}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{321}}{2*1}=\frac{2+2\sqrt{321}}{2}
$